0=24x^2+29x-4

Solution for 0=24x^2+29x-4 equation:

0=24x^2+29x-4

We move all terms to the left:

0-(24x^2+29x-4)=0

We add all the numbers together, and all the variables

-(24x^2+29x-4)=0

We get rid of parentheses

-24x^2-29x+4=0

a = -24; b = -29; c = +4;
Δ = b2-4ac
Δ = -292-4·(-24)·4
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-35}{2*-24}=\frac{-6}{-48}
=1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+35}{2*-24}=\frac{64}{-48}
=-1+1/3
$